The rate constant for the reaction 2N2O5- 4NO2-O2is 3-0-10-5 sec-1- If the rate is 2-4-10-5 mol L-1 sec-1- then the concentration of N2O5 in mole L-1 is

Rate constant (k)=3×10^ 5 sec^ 1 Rate of reaction =2.40×10^ 5 mole L^ 1 sec^ 1 nbsp; Rate of reaction =k× [Molar conc. of N_2O_5] [N_2O_5]=2.40×10^ 53×10^ ...

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Standard XIII

Chemistry

Rate of Reaction

The rate cons...

Question

The rate constant for the reaction
$2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$
is $3.0 \times 10^{- 5} {sec}^{- 1}$ . If the rate is $2.4 \times 10^{- 5} m o l L^{- 1} {sec}^{- 1}$ , then the concentration of $N_{2} O_{5} (i n m o l e L^{- 1}$ ) is

1.4

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1.2

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0.004

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0.8

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Solution

The correct option is D $0.8$
$Rate constant (k) = 3 \times 10^{- 5} {sec}^{- 1}$
$Rate of reaction = 2.40 \times 10^{- 5} m o l e L^{- 1} {sec}^{- 1}$
$Rate of reaction = k \times [M o l a r c o n c . o f N_{2} O_{5}]$
$[N_{2} O_{5}] = \frac{2.40 \times 10^{- 5}}{3 \times 10^{- 5}} = 0.8 m o l L^{- 1}$

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Similar questions

Q. The rate constant for the reaction

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

3.0 \times 10^{- 5} {sec}^{- 1}

. If the rate is

2.4 \times 10^{- 5} m o l L^{- 1} {sec}^{- 1}

, then the concentration of

N_{2} O_{5} (i n m o l e L^{- 1}

) is

Q. The rate constant for the reaction,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

, is

3.0 \times 10^{- 5} s e c^{- 1}

. If the rate is

2.40 \times 10^{- 5}

mol

l i t r e^{- 1} s e c^{- 1}

, then the concentration of

N_{2} O_{5}

( in mol

l i t r e^{- 1}

) is:

Q. For the reaction,

2 N_{2} O_{5} ⇌ 4 N O_{2} + O_{2}

rate and rate constant are

2.40 \times 10^{- 5}

mol

L^{- 1} s^{- 1}

and

3 \times 10^{- 5} s^{- 1}

respectively, then calculate the concentration of

N_{2} O_{5}

Q. The rate constant for the reaction,

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

2 \times 10^{- 5} s^{- 1}

. If rate of reaction is

1.4 \times 10^{- 5} m o l L^{- 1} s^{- 1}

, what will be the concentration of

N_{2} O_{5}

in mol

L^{- 1}

Q. For a reaction

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

;
Initial concentration of

N_{2} O_{5}

7.2

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L^{- 1}

and after

20

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[N O_{2}] = 2.4

mol

L^{- 1}

, then what will be rate of decomposition of

N_{2} O_{5}

in mol

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m i n^{- 1}

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The rate constant for the reaction 2N2O5→4NO2+O2 is 3.0×10−5 sec−1. If the rate is 2.4×10−5 mol L−1 sec−1, then the concentration of N2O5 (in mole L−1) is

The correct option is D 0.8Rate constant (k)=3×10−5 sec−1 Rate of reaction=2.40×10−5 mole L−1 sec−1 Rate of reaction=k×[Molar conc. of N2O5] [N2O5]=2.40×10−53×10−5=0.8 mol L−1

The rate constant for the reaction
$2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$
is $3.0 \times 10^{- 5} {sec}^{- 1}$ . If the rate is $2.4 \times 10^{- 5} m o l L^{- 1} {sec}^{- 1}$ , then the concentration of $N_{2} O_{5} (i n m o l e L^{- 1}$ ) is