The rate of radiation from a black body at $0$ $^{o}$ C is $E$ . The rate of radiation from this black body at $273$ $^{o}$ C is :

2 E

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E / 2

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16 E

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E / 16

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Solution

The correct option is B $16 E$
As we know that: $E \propto T^{4}$
So, $\frac{E}{T_{1}^{4}} = \frac{E_{2}}{T_{2}^{4}}$
$E_{2} = \frac{T_{2}^{4} \times E}{T_{1}^{4}} = \frac{546^{4}}{273^{4}}$
$E_{2} = 16 E$

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The rate of radiation of a black body at $0^{o} C$ is E J/sec. The rate of radiation of this black body at $273^{o} C$ will be

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