Question

The rate of radiation of a black body at $0^0$ C is EJ/sec. The rate of radiation of this black body at ${273}^0$ C will be

• A. 16 E
• B. 8 E
• C. 4 E
• D. E

Answer 1

The correct option is A

16 E

$\frac{E_1}{E_2}={\left(\frac{T_1}{T_2}\right)}^4\Rightarrow \frac{E}{E_2}={\left(\frac{273+0}{273+273}\right)}^4\Rightarrow E_2=16E.$