Question

The rate of reaction becomes 2 times for every 10 degree rise in temperature. How much will the rate of reaction will increase, when the temperature is increased from 30 degree C to 80 degree C?

Answer 1

As we know, $\frac{k_{t+10}}{k_t}=\frac{r_{t+10}}{r_t}=2$
For an increase of temperature to ${50}^{o}C$, i.e., 5 times, the rate increases by $2^5$ times, i.e., 32 times.