The ratio of number of lone pairs in the central atoms of NH3, H2O and XeF2 is:
A
3:2:1
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B
2:1:3
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C
1:2:3
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D
2:3:1
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Solution
The correct option is C1:2:3 NH3: 3 bond pairs and one lone pair because, out of 5 valence electrons of nitrogen, only 2 electrons are left to form a lone pair.
H2O: 2 bond pairs and two lone pairs because, out of 6 valence electrons of oxygen, 4 electrons are left to form 2 lone pairs.
XeF2: 2 bond pairs and three lone pairs because out of 8 valence electrons of xenon, 6 electrons are left to form 3 lone pairs.