Question

The ratio of slopes of maximum kinetic energy versus frequency and stopping potential $\left(V_0\right)$ versus frequency, in photoelectric effect gives:

• A. Charge of electron
• B. Planck's constant
• C. Work function
• D. Threshold frequency

Answer 1

Answer: (A)

Charge of electron

$hv=h{v}_0+e{V}_0$
$e{V}_0=hv-h{v}_0$
$V_0=\frac{h}{e}v-\frac{h}{e}{v}_0$ ...(i)
${\left(Slope\right)}_1=h/e$
${\left(KE\right)}_{max}=hv-h{v}_0$ .....(ii)
${\left(Slope\right)}_2=h$
${\left(Slope\right)}_2/{\left(Slope\right)}_1=\frac{h}{h/e}=e$.