Question

The reactant which is entirely consumed in reaction is known as limiting reagent.In the reaction $2A+4B\to 3C+4D$, when 5 moles of A react with 6 moles of B,then


A) Which is the limiting reagent

B)Calulate the amount of C Formed.

Answer 1

The limiting reagent is the reactant that is
completely used up in a reaction, and thus
determines when the reaction stops.

$2A+4B\to 3C+4D$
From reaction, we know that
2 moles of A react with = 4 moles of B
5 moles of A will react with = 10 moles of B

But, there is only 6 moles of B. So, B will be
consumed first in the reaction. Thus, B will act
as limiting reagent in the reaction.

Conclusion:

From the above analysis it is concluded that B
is the limiting reagent.

B.)

Amount of C formed
$2A+4B\to 3C+4D$
Since, B is the limiting agent.

From reaction,
4 moles of B gives = 3 moles of C
6 moles of B will give = $(3\times 6)/\left(4\right)$ moles of C
= 4.5 moles of C

Conclusion:
From the above analysis it is concluded that B is
the limiting reagent and the amount of $“C”$ formed is $4.5\text{mol}$.