The reaction of $C l_{2}$ gas with cold dilute and hot concentrated NaOH in water give sodium salt of two (different) oxoacids of chlorine P and Q respectively. The $C l_{2}$ gas reacts with $S O_{2}$ gas, in presence of charcoal to give a product R. R reacts with white phosphorous to give a compound S. On hydrolysis, S gives an oxoacid of phosphorous T.
R, S and T, respectively are:

S O_{2} C l_{2}, P C l_{5}

and

H_{3} P O_{4}

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S O_{2} C l_{2}, P C l_{3}

and

H_{3} P O_{3}

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S O C l_{2}, P C l_{3}

and

H_{3} P O_{2}

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S O_{2} C l_{2}, P C l_{5}

and

H_{3} P O_{4}

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Solution

The correct option is A $S O_{2} C l_{2}, P C l_{5}$ and $H_{3} P O_{4}$
$C l_{2} + S O_{2} i n p r e s e n c e o f - ------- \to c h a r c o a l S O_{2} C l_{2} 10 S O_{2} C l_{2} (R) + P_{4} \to 4 P C l_{5} (S) + 10 S O_{2} P C l_{5} (S) + 4 H_{2} O \to H_{3} P O_{4} (T) + 5 H C l$

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Similar questions

Q. Paragraph 2
The reactions of

C l_{2}

gas with cold-dilute and hot-concentrated NaOH in water give soduum salts fo two different oxoacids of chlorine, P and Q, respectively. The

C l_{2}

gas reacts with

S O_{2}

gas, in presence of charcoal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.

4. R, S and T, respectively, are
(IIT-JEE, 2013)

Q. The reaction of

C l_{2}

gas with cold dilute and hot concentrated NaOH in water give sodium salt of two (different) oxoacids of chlorine P and Q respectively. The

C l_{2}

gas reacts with

S O_{2}

gas, in presence of charcoal to give a product R. R reacts with white phosphorous to give a compound S. On hydrolysis, S gives as oxoacid of phosphorous T.
P and Q, respectively, are the sodium salts of:

The reactions of $C l_{2}$ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxoacids of chlorine, P and Q, respectively. The $C l_{2}$ gas reacts with $S O_{2}$ gas, in presence of charcoal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.

3. P and Q, respectively, are the sodium salts of

Q. A violet compound of manganese (F) decomposes on heating to liberate oxygen and compounds (Q) and (R) of manganese is formed. Compound (R) reacts with KOH in the presence of potassium nitrate to give compound (Q). On heating compound (R) with conc.

H_{2} S O_{4}

and NaCl, chlorine gas is liberated and a compound (S) of manganese along with other products is formed. Compounds P to S are:

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The correct option is A SO2Cl2,PCl5 and H3PO4Cl2+SO2in presence of−−−−−−−−→charcoalSO2Cl210 SO2Cl2(R)+P4→4PCl5(S)+10 SO2PCl5(S)+4H2O→H3PO4(T)+5HCl

The correct option is A $S O_{2} C l_{2}, P C l_{5}$ and $H_{3} P O_{4}$
$C l_{2} + S O_{2} i n p r e s e n c e o f - ------- \to c h a r c o a l S O_{2} C l_{2} 10 S O_{2} C l_{2} (R) + P_{4} \to 4 P C l_{5} (S) + 10 S O_{2} P C l_{5} (S) + 4 H_{2} O \to H_{3} P O_{4} (T) + 5 H C l$