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Halohydrin Reaction

The reaction ...

Question

The reaction of propene with $H O C l (C l_{2} + H_{2} O)$ with ethene proceeds through the intermediate:

C H_{3} - C H C l - C H_{2}^{+}

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C H_{3} - C H^{+} - C H_{2} - O H

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C H_{3} - C H^{+} - C H_{2} - C l

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C H_{3} - C H (O H) - C H_{2}^{+}

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Solution

The correct option is C $C H_{3} - C H^{+} - C H_{2} - C l$
$C H_{3} C H = C H_{2} + H O C l (C l_{2} + H_{2} O) ⟶ C H_{3} - C H^{+} - C H_{2} C l most stable intermidiate + O H^{-}$
This is due to stability of carbocation . Secondary carbocation is more stable than primary.

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Similar questions

H O C l (C l_{2} + H_{2} O)

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

S_{N} 2

c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

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