The reaction ROH + HCl $\Leftrightarrow$ RCl + $H_{2} O$ is reversible, so for the completion of the reaction we use along with the reactants.

Conc.

H_{2} S O_{4}

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P_{2} O_{5}

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H_{3} P O_{4}

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N_{2} O_{5}

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Solution

The correct option is A Conc. $H_{2} S O_{4}$
$R - O H + H C l C o n c . H_{2} S O_{4} - ------- \to R - C l + H_{2} O$
$C o n c . H_{2} S O_{4}$ acts as a dehydrating agent.

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Similar questions

R C l + N a O H (a q .) ⟶ R O H + N a C l

= k [R C l]

R C l + N a O H (a q .) \to R O H + N a C l

R a t e = k_{1} [R C l] .

R C l + N a O H (a q) \to R O H + N a C l

R a t e = k [R C l]

R C l + N a O H (a q) \to R O H + N a C l

R a t e = k [R C l]

The rate law for the reaction:
$R C l + N a O H \to R O H + N a C l$ is given by;
Rate = $k [R C l]$ . The rate of this reaction is

(IIT-JEE, 1990)

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