The reactivity of different nucleophiles $(N H_{2}^{-}, C H_{3} C O O^{-}, O H^{-})$ is in the order:

N H_{2}^{-} < C H_{3} C O O^{-} < O H^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C O O^{-} < O H^{-} < N H_{2}^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N H_{2}^{-} < O H^{-} < C H_{3} C O O^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C O O^{-} < N H_{2}^{-} < O H^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C H_{3} C O O^{-} < O H^{-} < N H_{2}^{-}$
More stable the anion, less will be its nucleophilicity. Acetate is the most stabilised ion since it has equivalent resonance structures. Electronegativity of $O$ is greater than $N$ hence it can accomodate negative charge more easily. Thus the order will be: $C H_{3} C O O^{-} < O H^{-} < N H_{2}^{-}$

Suggest Corrections

Similar questions

(N H_{2}^{-}, C H_{3} C O O^{-}, O H^{-})

(H O^{-}, C H_{3} C O O^{-}, P h O^{-}, C H_{3} O^{-}) .

{S_{N}}^{2}

H_{2} O

^{-} O C H_{3},^{-} O H

C H_{3} C O O^{-}

A (F_{3} C - \equiv - C F_{3})

C H_{3} O^{⊝}

C_{3} H_{5}^{⊝}

C H_{3} C O O^{⊝}

C H_{3} S O_{3}^{⊝}

S_{N} 2

H_{2} O, C H_{3} O^{-}, O H^{-}, C H_{3} C O O^{-}

Join BYJU'S Learning Program