Question

The reading of centrigrade thermometre concide with that of Fahrenheit thermometer in a liquid. The temp of the liquid is

• A. ${-40}^{0}C$
• B. ${313}^{0}C$
• C. $0^{0}C$
• D. $100^{0}C$

Answer 1

The correct option is A ${-40}^{0}C$

Let $x$ be the temperaure at which ${}^{0}C$ and ${}^{0}F$ coincide.

We have,

$\frac{x-32}{180}=\frac{x}{100}$

$x-32=\frac{180x}{100}$

$x-\frac{180x}{10}=32$

$100x-180x=3200$

$-180x=3200$

$x=-\frac{3200}{80}=-{40}^{0}C$