The correct options are
A LiAlH4
B BH3 in THF
BH3 in THF being a strong reducing agent, can efficiently convert carboxylic acid into the corresponding primary alcohol. Also, LiAlH4 being a strong reducing agent, releases H− ions in enough quantity to convert carboxylic acid to the corresponding alcohol. So, ethanoic acid can be converted to ethanol using BH3 in THF and LiAlH4.