Question

The relation between $X$ and $Y$ is given as $\frac{2}{3-X}(X+4)+3=\frac{Y+2}{3-X}-5$. Find the value of $X$, if $Y=6$.

• A. -6
• B. -4
• C. -5
• D. -3

Answer 1

The correct option is C -5

Given:

$\frac{2}{3-X}(X+4)+3=\frac{Y+2}{3-X}-5$

Take LCM $(3-X)$ on both sides,

$\frac{2(X+4)+3(3-X)}{3-X}=\frac{Y+2-5(3-X)}{3-X}$

The denominator of all the terms are same. So, by removing the denominator,

$2(X+4)+3(3-X)=Y+2-5(3-X)$

$⟹2X+8+9-3X=Y+2-15+5X$

$⟹2X-3X-5X=Y+2-15-8-9$

$⟹-6X=Y-30$

$⟹-6X=6-30$

$⟹-6X=-24$

$⟹6X=24$

$⟹X=4$

$\therefore$ The value of $X$ is 4.