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Question

The resistance in the left and right gaps of a balanced metre bridge are R1 and R2. The balanced point is 50 cm. If a resistance of 24Ω is connected in parallel toR2, the balance point is 70 cm. The value of R1 orR2 is

A
12Ω
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B
8Ω
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C
16Ω
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D
32Ω
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Solution

The correct option is D 32Ω
Balanced condition for 1st case: R1R2=l100l=5010050=1
so R1=R2
In 2nd case : when 24 Ω is connected in parallel to R2 , the resistance of R2 arm becomes RP=24R224+R2
now balance condition is R1RP=7010070
or R1RP=7/3
or R2=(7/3)RP as R1=R2
or R2=(7/3)24R224+R2
or 24R2+R22=56R2
or R22=32R2
or R2=32Ω

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