The resistance of a bulb filament is 100Ω at a temperature of 100oC. lf its temperature coefficient of resistance be 0.005per∘C, its resistance will become 200Ω at a temperature of
A
200oC
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B
300oC
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C
400oC
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D
500oC
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Solution
The correct option is B300oC
We know that
Tt=To(1+αΔT)
On putting the values we get
200=100[1+(0.005×ΔT)] (governing equation formed according to the statement of question)