The resistance of a wire of $100 c m$ length is $10 Ω$ . Now, it is cut into $10$ equal parts and all of them are twisted to form a single bundle. Its resistance is:

1 Ω

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0.5 Ω

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5 Ω

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0.1 Ω

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Solution

The correct option is C $0.1 Ω$
Resistance of the 10 parts in series is $10 Ω$
Resistance of one part $= 1 Ω$
Single bundle implies all are in parallel
$\Rightarrow R_{e q} = \frac{1 \times 1....10 t i m e s}{1 + 1 + 1..10 t i m e s} = \frac{1}{10} = 0.1 Ω$

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The resistance of a wire of 100 cm length is 10Ω. Now, it is cut into 10 equal parts and all of them are twisted to form a single bundle. Its resistance is:

The correct option is C 0.1ΩResistance of the 10 parts in series is 10ΩResistance of one part =1ΩSingle bundle implies all are in parallel⇒Req=1×1....10times1+1+1..10times=110=0.1Ω

The resistance of a wire of $100 c m$ length is $10 Ω$ . Now, it is cut into $10$ equal parts and all of them are twisted to form a single bundle. Its resistance is:

The correct option is C $0.1 Ω$
Resistance of the 10 parts in series is $10 Ω$
Resistance of one part $= 1 Ω$
Single bundle implies all are in parallel
$\Rightarrow R_{e q} = \frac{1 \times 1....10 t i m e s}{1 + 1 + 1..10 t i m e s} = \frac{1}{10} = 0.1 Ω$