The resistance of the wire in the platinum resistance thermometer at ice point is 5Ω and at steam point is 5.25Ω. When the thermometer is inserted in an unknown hot bath its resistance is found to be 5.5Ω. The temperature of the hot bath is?
Given,
Resistance at ice point,R0=5Ω,
Resistance at steam point,R100=5.25Ω,
Resistance when dip in unknow,R0=5Ω,R100=5.25Ω,Rt=5.5Ω
R100=R0(1+α100)
α=R100−R0R0×100=5.25−55×100=5×10−4 oC−1
Let the temperature of hot bath = toC
Rt=R0(1+αt)
t=Rt−R0Roα=5.5−55×(5×10−4)=200 oC
Temperature of bath is 200 oC