The roots of the equation $x^{3} - 3 x - 2 = 0$ , are:

- 1, - 1, 2

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- 1, 1, - 2

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- 1, - 2, - 3

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- 1, - 1, - 2

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Solution

The correct option is D $- 1, - 1, 2$
The given equation is $x^{3} - 3 x - 2 = 0$
$\Rightarrow (x + 1) (x^{2} - x - 2) = 0$
$\Rightarrow (x + 1) (x + 1) (x - 2) = 0$
$\Rightarrow x = - 1, - 1, 2$

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