MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Crystal Field Split in Octahedral Complexes

The same amou...

Question

The same amount of Zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide. What will be the ratio of volumes of hydrogen evolved ?

A

1:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

1:4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

2:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

9:4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1:1

$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$

$Z n + 2 N a O H \to N a Z n O_{2} + H_{2}$

Ratio of volumes of hydrogen evolved = $1 / 1 = 1 : 1$

Suggest Corrections

thumbs-up

0

Similar questions

Q. When some amount of zinc is treated separately with an excess of sulphuric acid and excess of sodium hydroxide solution the ratio of volumes of hydrogen evolved will be:

Q. When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is:

Q. When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is

X : Y

. Find the value of

\frac{X}{Y}

.

Q. When same amount of zinc is treated separately with excess of 1

H_{2} S O_{4}

N a O H

, the ratio of volumes of

H_{2}

Q. When the same amount of zinc metal is treated separately with excess of

H_{2} S O_{4}

N a O H

, the ratio of the volumes of

H_{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Octahedral Complexes

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Crystal Field Split in Octahedral Complexes

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon