The same retarding force is applied to stop a train, if the speed is doubled then the stopping distance will be

same

No worries! We‘ve got your back. Try BYJU‘S free classes today!

doubled

No worries! We‘ve got your back. Try BYJU‘S free classes today!

half

No worries! We‘ve got your back. Try BYJU‘S free classes today!

four times

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D four times
We know that $s = \frac{- (v^{2} - u^{2})}{2 a}$ (negative sign for retarding force)
Since force is constant, thus acceleration is constant.
In first case with speed u, it stops when v=0, thus $s = \frac{- (0 - u^{2})}{2 a} = \frac{u^{2}}{2 a}$
In second case with speed = 2u, $s = \frac{- (0 - {(2 u)}^{2})}{2 a} = \frac{4 u^{2}}{2 a}$
Thus it is $4$ times

Suggest Corrections

Similar questions

The same retarding force is applied to stop a train. The train stops after 80 m. If the speed is doubled, then the distance will be

Q. A retarding force is applied to stop a train. The train stops after 80 m. If the speed is doubled, then the distance travelled when same retarding force is applied is

When a train is stopped by applying break it stops after travelling a distance of 50 m. If speed of train is doubled and same retarding force is applied then it stops after travelling a distance of:

Q. Uniform constant retarding force is applied in order to stop a truck. If its speed is doubled then the distance travelled by it will be

Join BYJU'S Learning Program