The shape of $I F_{7}$ is

Tetrahedral

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Trigonal bipyramidal

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Octahedral

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Pentagonal bipyramidal

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Solution

The correct option is D Pentagonal bipyramidal
Let's apply VSEPR and hybridisation theory here.

Iodine has 7 valence electrons and there are 7 fluorine atoms.

So, electron pairs (e.p) = $\frac{7 + 7}{2} = 7$

From this, we can say the hybridisation will be $s p_{3} d_{3}$

So, the structure will be pentagonal bipyramidal.

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