Question

The species that has the same number of electrons as ${}_{17}^{35}\text{Cl}$ is

• A. ${}_{16}^{32}\text{S}$
• B. ${}_{16}^{34}{\text{S}}^{+}$
• C. ${}_{18}^{40}{\text{Ar}}^{+}$
• D. ${}_{16}^{35}{\text{S}}^{2-}$

Answer 1

The correct option is C ${}_{18}^{40}{\text{Ar}}^{+}$

Number of electron in ${}_{17}^{35}Cl=17$

Number of electron in ${}_{16}^{32}S=16$

Number of electron in ${}_{16}^{34}{S}^{+}=16-1=15$

Number of electron in ${}_{18}^{40}A{r}^{+}=18-1=17$

Number of electron in ${}_{16}^{35}{S}^{2-}=16+2=18$

So option C is correct