Question

The specific conductance of a $N/10$ KCl solution at ${18}^{\circ }C$ is $1.12\times {10}^{-2}mhoc{m}^{-1}$. The resistance of the solution contained in the cell is found to be 65 ohms. Calculate the cell constant.

• A. $0.728c{m}^{-1}$
• B. $0.928c{m}^{-1}$
• C. $0.428c{m}^{-1}$
• D. $0.328c{m}^{-1}$

Answer 1

The correct option is A $0.728c{m}^{-1}$

The resistance R of the solution contained in the cell is found to be 65 ohms.
The conductance C of the solution is $C=\frac{1}{R}=\frac{1}{65}=0.015385oh{m}^{-1}$
The cell constant is the ratio of specific conductance to conductance.
Cell constant $=\frac{1.12\times {10}^{-2}mhoc{m}^{-1}}{0.015385oh{m}^{-1}}=0.728c{m}^{-1}$