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Equivalent, Molar Conductivity and Cell Constant

The specific ...

Question

The specific conductivity of $0.02 M K C l$ solution at $25^{\circ} C$ is $2.768 \times 10^{- 3} o h m^{- 1} c m^{- 1}$ . The resistance of this solution at $25^{\circ} C$ when measured with a particular cell was $250.2 o h m$ . The resistance of $0.01 M C u S O_{4}$ solution at $25^{\circ} C$ measured with the same cell was $8331 o h m$ . Calculate the molar conductivity of the copper sulphate solution.

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Solution

Cell constant $= \frac{Sp. cond. of KCl}{Conductance of KCl}$
$= \frac{2.768 \times 10^{- 3}}{1 / 250.2}$
$= 2.768 \times 10^{- 3} \times 250.2$
For $0.01 M C u S O_{4}$ solution
$S p . c o n d u c t i v i t y = C e l l c o n s t a n t \times C o n d u c t a n c e$
$= 2.768 \times 10^{- 3} \times 250.2 \times \frac{1}{8331}$
Molar conductance $= S p . c o n d . \times \frac{1000}{C}$
$= \frac{2.768 \times 10^{- 3} \times 250.2}{8331} \times \frac{1000}{1 / 100} = 8.312 o h m^{- 1} c m^{2} m o l^{- 1}$ .

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