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Nernst Equation

The standard ...

Question

The standard electrode potential of Cu/Cu $^{+ 2}$ electrode is 0.336. It corresponds to the reaction:

C u \to C u^{+ 2} + 2 e^{-}

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\frac{1}{2} C u^{+ 2} + e^{-} \to \frac{1}{2} C u

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C u^{+ 2} + 2 e^{-} \to C u

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2 C u^{+} \to C u + 2 e^{-}

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Solution

The correct option is A $C u \to C u^{+ 2} + 2 e^{-}$
Cu is oxidised to $C u^{2 +}$
$∴$ The reaction is $C u \to C u^{2 +} + 2 e^{-}$
Hence, option A is correct.

Suggest Corrections

Similar questions

C u^{2 +} + 2 e^{-} ⟶ C u

E^{0} = 0.337 V

C u^{2 +} + e^{-} ⟶ C u^{+}

E^{0} = 0.153 V

E^{0}

C u^{+} + e^{-} ⟶ C u

C u^{2 +} + 2 e^{-} \to C u, E^{\circ} = 0.337 V

C u^{2 +} + e^{-} \to C u^{+}, E^{\circ} = 0.153 V

E^{\circ}

C u^{+} + e^{-} \to C u

{C u}^{2 +} + {2 e}^{-} \to C u, E^{o} = + 0.337 V

{C u}^{2 +} + e^{-} \to C u^{+} E^{o} = + 0.153 V

E^{0}

{C u}^{+} + e^{-} \to C u

C u^{2 +} + 2 e^{-} \to C u

[C u^{2 +}]

E

O A = 0.34

C u | C u^{2 +} (0.1 M)

C u^{2 +} | C u^{+}

C u^{+} | C u

C u^{2 +} | C u

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