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Byju's Answer
Standard XII
Chemistry
Nernst Equation
The standard ...
Question
The standard electrode potential of Cu/Cu
+
2
electrode is 0.336. It corresponds to the reaction:
A
C
u
→
C
u
+
2
+
2
e
−
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B
1
2
C
u
+
2
+
e
−
→
1
2
C
u
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C
C
u
+
2
+
2
e
−
→
C
u
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D
2
C
u
+
→
C
u
+
2
e
−
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Solution
The correct option is
A
C
u
→
C
u
+
2
+
2
e
−
Cu is oxidised to
C
u
2
+
∴
The reaction is
C
u
→
C
u
2
+
+
2
e
−
Hence, option A is correct.
Suggest Corrections
0
Similar questions
Q.
1.
C
u
2
+
+
2
e
−
⟶
C
u
,
E
0
=
0.337
V
2.
C
u
2
+
+
e
−
⟶
C
u
+
,
E
0
=
0.153
V
Electrode potential,
E
0
for the reaction
C
u
+
+
e
−
⟶
C
u
Q.
Given:
(i)
C
u
2
+
+
2
e
−
→
C
u
,
E
∘
=
0.337
V
(ii)
C
u
2
+
+
e
−
→
C
u
+
,
E
∘
=
0.153
V
Electrode potential,
E
∘
for the reaction,
C
u
+
+
e
−
→
C
u
, will be
Q.
Given (i)
C
u
2
+
+
2
e
−
→
C
u
,
E
o
=
+
0.337
V
(ii)
C
u
2
+
+
e
−
→
C
u
+
E
o
=
+
0.153
V
Electrode potential,
E
0
for the reaction will be:
C
u
+
+
e
−
→
C
u
Q.
For the reaction,
C
u
2
+
+
2
e
−
→
C
u
; log
[
C
u
2
+
]
vs
E
graph is of type as shown in figure where
O
A
=
0.34
V, the electrode potential of the half-cell of
C
u
|
C
u
2
+
(
0.1
M
)
will be:
Q.
The standard electrode potentials of
C
u
2
+
|
C
u
+
and
C
u
+
|
C
u
electrodes are +0.18V and +0.50V. The potential of
C
u
2
+
|
C
u
electrode is _________.
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