The structure of $X e F_{4}$ is :

planar

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tetrahedral

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square planar

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pyramidal

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Solution

The correct option is C square planar
$X e F_{4}$ has $s p^{3} d^{2}$ -hybridized $X e$ atom having two lone pair of electrons and thus, octahedral geometry changes to square planar due to lone pair effect.

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