The sum of the oxidation state of the nitrogen atom in hyponitrous acid, nitric acid and nitrous acid is ______.

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Solution

Hyponitrous acid,
$N_{2} (O H)_{2}$
$2 x + 2 (- 1) = 0$
$2 x = 2$
$x = + 1$

Nitric acid,
$H N O_{3}$
$1 + x + 3 (- 2) = 0$
$x = + 5$
Nitrous acid,
$H N O_{2}$
$1 + x + 2 (- 2) = 0$
$x = + 3$
Sum of the oxidation state of the nitrogen atom in hyponitrous acid, nitric acid and nitrous acid is $1 + 5 + 3 = 9$ .

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