Let the first multiple of 5 be x.
Then the other multiple of 5 will be x + 5 and their sum = 55
Therefore, x + x + 5 = 55
⇒2x+5=55
⇒2x=55−5
⇒2x=50
⇒x=502
⇒x=25
Therefore, the decond multiples of 5, i.e., x + 5 = 25 + 5 = 30
Therefore, the two consecutive multiples of 5 whose sum is 55 are 25 and 30.