Question

The sum of two numbers is 4 more than the twice of the difference between the two numbers. One of the two numbers is three more than the other number.

• A. (13/2, 7/2)
• B. (1, 3)
• C. (4/5, 3)
• D. (1, 2)

Answer 1

The correct option is A

(13/2, 7/2)

Let one number be x and the other number be y

x + y = 4 + 2(x - y) [given]

$\Rightarrow$ x + y = 4 + 2x - 2y

$\Rightarrow$ x - 3y + 4 = 0 ------------(i)

x = 3 + y -----------(ii) [given]

Substitute (ii) in (i), (3 + y) - 3y + 4 = 0

$\Rightarrow$ y = $\frac{7}{2}$

Substitute the value of y in (ii), x = 3 + $\frac{7}{2}$ = $\frac{13}{2}$