Question

The sum of two numbers is $99$. If one number is $20$% more than the other; find the two numbers.

• A. $45$ and $33$
• B. $54$ and $45$
• C. $66$ and $35$
• D. $63$ and $65$

Answer 1

Answer: (B)

$54$ and $45$

Let the 1st number be $x$.

So, the second number will be $99-x$.

As per the given condition,

$x=99-x+\frac{20}{100}(99-x)$

$x=99-x+19.8-0.2x$

$2.2x=118.8$

$x=54$

The other number is $99-54=45$