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Standard XII

Physics

Thermodynamic Processes

The temperatu...

Question

The temperature of gas is increased from $200 K$ to $600 K$ at a constant pressure. If initially the volume of gas is $10 cc$ , then the final volume of the gas will be (in $cc$ )

30

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20

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3.33

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10

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Solution

The correct option is A $30$
Since, pressure is constant
$V \propto T$
$\Rightarrow \frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}}$
Given, $V_{1} = 10 cc; T_{1} = 200 K; T_{2} = 600 K$
$∴ V_{2} = \frac{V_{1} T_{2}}{T_{1}} = \frac{10 \times 600}{200} = 30 cc$

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The temperature of gas is increased from 200 K to 600 K at a constant pressure. If initially the volume of gas is 10 cc, then the final volume of the gas will be (in cc)

The correct option is A 30Since, pressure is constant V∝T ⇒V1V2=T1T2 Given, V1=10 cc;T1=200 K;T2=600 K ∴V2=V1T2T1=10×600200=30 cc

The temperature of gas is increased from $200 K$ to $600 K$ at a constant pressure. If initially the volume of gas is $10 cc$ , then the final volume of the gas will be (in $cc$ )

The correct option is A $30$
Since, pressure is constant
$V \propto T$
$\Rightarrow \frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}}$
Given, $V_{1} = 10 cc; T_{1} = 200 K; T_{2} = 600 K$
$∴ V_{2} = \frac{V_{1} T_{2}}{T_{1}} = \frac{10 \times 600}{200} = 30 cc$