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Question

The temperature of gas is increased from 400 K to 600 K keeping the volume of the gas constant. If initially the gas exerted a pressure of 3 kPa on the walls of the container, then the final pressure of the gas is (in kPa)
  1. 6
  2. 4.5
  3. 0.06
  4. 0.045


Solution

The correct option is B 4.5
Given,
Ti=400 K;Tf=600 K;Pi=3 kPa
At constant volume,
PiTi=PfTf
Pf=PiTfTi=3×600400=4.5 kPa

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