CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The temperature of the cold junction of thermocouple is 0oC and the temperature of hot junction is ToC. The emf is E=16T0.04T2μV. The inversion temperature Ti is

A
300oC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
200oC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
500oC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
400oC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B 400oC
The inversion temperature (Ti) of a thermocouple is that temperature of hot junction, at which thermo emf becomes zero i.e.
At T=Ti, E=0
Putting these values in the given equation:
E=16T0.04T2
0=16Ti0.04T2i
0.04T2i=16Ti
Ti=16/0.04=400oC

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Perpendicular Distance of a Point from a Plane
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon