Question

The tetrachloro complexes of $Ni\left(II\right)$ and $Pd\left(II\right)$ are respectively:

(atomic number of $Ni$ and $Pd$ are $28$ and $46$ respectively)

• A. Diamagnetic and Diamagnetic
• B. Paramagnetic and Paramagnetic
• C. Diamagnetic and Paramagnetic
• D. Paramagnetic and Diamagnetic

Answer 1

The correct option is D Paramagnetic and Diamagnetic

As we move from the first to the second transition series, crystal field splitting increases for a given ligand. Thus, $[PdC{l}_4{]}^{2-}$ is a sqare planner complex and $[NiC{l}_4{]}^{2-}$ is a tetrahedral complex. Hence, $[NiC{l}_4{]}^{2-}$ is paramagnetic and a high spin complex whereas $[PdC{l}_4{]}^{2-}$ is diamagnetic and a low spin complex.