Question

The $\left[Ti\right(NCS{)}_6{]}^{3-}$ ion exhibits a single absoption band at $544nm$. What will be the crystal field splitting energy of the complex? $(\text{Planck constant}=6.626\times {10}^{-34}Js)$

• A. $2.65\times {10}^{18}J$
• B. $12.5\times {10}^{-19}J$
• C. $2.65\times {10}^{-18}J$
• D. $3.65\times {10}^{-19}J$

Answer 1

The correct option is D $3.65\times {10}^{-19}J$

The expression for the crystal field splitting energy is
$=h\nu =\frac{hc}{\lambda }$
where, h is the Planck's constant
$v$ is the frequency of light
$c$ and $\lambda$ are the speed and the wavelength of light respectively.
Substitute values in the above expression,
${\Delta }_o=\frac{(6.626\times {10}^{-34}Js)\times (3.0\times {10}^{8}m{s}^{-1})}{544\times {10}^{-9}m}=3.65\times {10}^{-19}J$