Question

The total Number of three digit numbers possible , If product of those three digit is $20$, is

• A. $6$
• B. $9$
• C. $12$
• D. $15$

Answer 1

Answer: (B)

$9$

The product of $3$ digit number is $20$

Factors of $20$ are $1,2,4,5,10,20$

The possible numbers can be selected for one set are $1,4,5;2,2,5$

The first set can be arranged in $3!=6$ ways

The second set can be arranged in $\frac{3!}{2!}=3$ ways

Total number of ways are $9$