The treatment of $R_{3} M g X$ with ethyl formate leads to the formation of:

R C H O

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{C H}_{3} {C H}_{2} O R

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R C H O H C_{2} H_{5}

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C_{2} H_{5} O H

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Solution

The correct option is A $R C H O$
Ethyl formate is written as $H C O O C_{2} H_{5}$ . The reaction is as follows
$H C O O C_{2} H_{5} + R M g X \to R C H O + M g (O C_{2} H_{5}) X$
Hence the correct answer is option A

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C H_{3} C O O C_{2} H_{5} + H_{2} O H^{+} - ----- \to C H_{3} C O O H + C_{2} H_{5} O H

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C H_{3} - B r | C | C_{2} H_{5} - C H_{3}

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