The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield an earning of Rs 2000 per $m^{2}$ a year. A company hired one of its walls for 6 months. How much rent did it pay?

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Solution

$A c c o r d i n g t o H e r o n^{'} s f o r m u l a t h e a r e a (A) o f t r i a n g l e w i t h s i d e s a, b & c i s g i v e n a s A = \sqrt[2]{[s (s - a) (s - b) (s - c)]} w h e r e 2 s = (a + b + c) . T h e t r i a n g u l a r s i d e w a l l s h a v e t h e f o l l o w i n g d i m e n s i o n s : a = 13 m, b = 14 m, c = 15 m . H e n c e 2 s = (13 + 14 + 15) = 42 S o, t h e a r e a o f o n e t r i a n g u l a r s i d e w a l l = \sqrt[2]{[21 (21 - 13) (21 - 14) (21 - 15)]} = \sqrt[2]{[21 (8) (7) (6)]} = \sqrt[2]{[3 \times 7 \times 2 \times 2 \times 2 \times 7 \times 2 \times 3]} = \sqrt[2]{[(2 \times 2 \times 3 \times 7) (2 \times 2 \times 3 \times 7)]} = (2 \times 2 \times 3 \times 7) = 84 T h e a d v e r t i s e m e n t s y i e l d = R s . 2000 p e r f o r 1 y e a r . S i n c e t h e c o m p a n y h i r e d 1 s u c h w a l l f o r 6 m o n t h s, s o t h e a m o u n t o f r e n t t o b e p a i d a t t h i s r a t e f o r 6 m o n t h s = \frac{84 \times 2000}{2} = 84 \times 1000 = R s . 84000$

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The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield an earning of Rs 2000 per m2 a year. A company hired one of its walls for 6 months. How much rent did it pay?

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield an earning of Rs 2000 per $m^{2}$ a year. A company hired one of its walls for 6 months. How much rent did it pay?