The type of Hybrid orbitals used by Chlorine atom in $C l O_{2}^{-}$ ion is:

s p^{3}

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s p^{2}

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s p

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1 & 2

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Solution

The correct option is B $s p^{3}$
$C l O_{2}^{-}$ has $s p^{3}$ hybridization
Ground state electronic hybridization of Cl = $3 s^{2} 3 p^{5}$
Excited state electronic configuration of Cl = $3 s^{2} 3 p^{3} 3 d 1$
Electronic configuration of O = $2 s^{2} 2 p^{4}$
Hence Cl undergoes $s p^{3}$ hybridization.

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Similar questions

The type of hybrid orbitals used by the chlorine atom in $C l O_{2}^{-}$ is

C l O_{2}^{-}

C l O^{-}, C l O_{2}^{-}, C l O_{3}^{-}

C l O_{4}^{-}

s p

s p^{2}

s p^{3}

Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

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