Question

The type of hybridization involved in the metal ion of $\left[Ni\right(H_{2}O{)}_6{]}^{2+}$ complex is

• A. $d^{3}s{p}^2$
• B. $s{p}^3{d}^2$
• C. $s{p}^3$
• D. $ds{p}^2$

Answer 1

The correct option is B $s{p}^3{d}^2$

The oxidation state of $Ni$ in $\left[Ni\right(H_{2}O{)}_6{]}^{2+}$ ion is +2, and configuration $3d^8$.
Water is a weak field ligand so no pairing occur leaving two unpaired electron in 3d. Six vacant orbitals form $s{p}^3{d}^2$ hybridised octahedral outer orbitals complex.