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Question

The unit vector perpendicular to each of the vectors 2ij+k and 3i+4jk is

A
3i+5j+11k
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B
(3i+5j+11k)/155
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C
(3i+5j+11k)/(155)
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D
None of these
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Solution

The correct option is C (3i+5j+11k)/(155)
We know that a×b is vector perpendicular to the plane of a and b
Therefore unit vector perpendicular to the plane of a and b =a×b|a×b|
Now a×b=(2ij+k)×(3i+4jk)
=∣ ∣ijk211341∣ ∣=i(14)+j(3+2)+k(8+3)=3i+5j+11k
unit vector parallel to a×b
=a×b|a×b|=3i+5j+11k(32+52+112)
=3i+5j+11k155

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