The value obtained by subtracting the $10^{t h}$ term of an AP from the $17^{t h}$ term is $56$ . Find the common difference.

7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $8$
In an Arithmetic Progression the general term of an A.P. is given by $T_{n}$ :
$T_{n} = a + (n - 1) d$
According to the statement:
$T_{17} - T_{10} = 56$
$a + (17 - 1) d - [a + (10 - 1) d] = 56$
$a + 16 d - [a + 9 d] = 56$
$a + 16 d - a - 9 d = 56$
$7 a = 56$
$d = 8$

Suggest Corrections

Similar questions

17^{t h}

A P

10^{t h}

7

The $17^{t h}$ term of an AP exceeds its $10^{t h}$ term by 7. Its common difference is ___

The $17^{t h}$ term of an AP exceeds its $10^{t h}$ term by 7. The common difference of the AP is

The $17^{t h}$ term of an AP exceeds its $10^{t h}$ term by 7. The common difference is 2.

17^{t h}

A . P

10^{t h}

7

d

Join BYJU'S Learning Program