Question

The value of $\tan {26}^{\circ }-\cot {64}^{\circ }$ equals

• A. $-1$
• B. $1$
• C. $0$
• D. $2$

Answer 1

Answer: (C)

$0$

$\tan {26}^{\circ }-\cot {64}^{\circ }=\tan ({90}^{\circ }-{64}^{\circ })-\cot {64}^{\circ }=\cot {64}^{\circ }-\cot {64}^{\circ }=0(\because \tan ({90}^{\circ }-\theta )=\cot \theta )$