The value of Ereduction of a hydrogen electrode at pH=0 and 298K, 1atm is:
A
0.59V
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B
0V
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C
−0.59V
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D
−0.059V
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Solution
The correct option is B0V We know,Ered=E∘cell−0.05911log1[H+]
The reduction reaction here is H++e−⟶12H2(g)
Given, pH=0⇒−log[H+]=0⇒[H+]=1M ∴Ered=0−0.05911log1=0V