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Question

The value of Ereduction of a hydrogen electrode at pH=0 and 298 K, 1 atm is:

A
0.59 V
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B
0 V
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C
0.59 V
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D
0.059 V
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Solution

The correct option is B 0 V
We know,Ered=Ecell0.05911log1[H+]
The reduction reaction here is
H++e12H2(g)
Given,
pH=0log[H+]=0[H+]=1 M
Ered=00.05911log1=0 V

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