Question

The value of
$k$ such that $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}$
lies in the plane $2x-4y+z=7$ is

• A. $7$
• B. $-7$
• C. no real value
• D. $4$

Answer 1

The correct option is A $7$

Given equation of straight line $\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}$

Since, the line lies in the plane $2x-4y+z=7$

$\therefore$ Point $(4,2,k)$ must satisfy the plane.

$\Rightarrow 8-8+k=7$

$\Rightarrow k=7$