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Thermodynamic Processes

The value of ...

Question

The value of $P V$ for 5.6 litres of an ideal gas at $NTP$ is

0.35 R T

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0.25 R T

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0.30 R T

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0.20 R T

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Solution

The correct option is B $0.25 R T$
Volume of one mole of an ideal gas at NTP is $22.4 l$
$∵ 5.6 l = \frac{1}{4}$ mole of an ideal gas.
Using ideal gas equation
$P V = n R T = \frac{1}{4} R T = 0.25 R T$

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