The value of sin[2tan−1(0.75)] is
(a) 0.75 (b) 1.5 (c) 0.96 (d) sin 1.5
(c) We have sin[2 tan−1(0.75)]=sin(2 tan−134) [∵ 0.75=75100=34]=sin[sin−12.341+916]=sin[sin−13/225/16]=sin[sin−1(4850)]=sin[sin−1(2425)]=2425=0.96