The values of IP1,IP2,IP3 and IP4 of an atom are 7.5eV,25.6eV,48.6eV and 170.6eV respectively. The electronic configuration of the atom will be:
A
1s2,2s2,2p6,3s1
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B
1s2,2s2,2p6,3s2,3p1
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C
1s2,2s2,2p6,3s2,3p3
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D
1s2,2s2,2p6,3s2
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Solution
The correct option is B1s2,2s2,2p6,3s2,3p1 Whenever there is a sudden increase in the ionisation potential, it indicates that the species had a stable configuration.
It is given that Ip4>>>Ip3, which indicate that the species attained stability by loosing 3 electrons.
So, option (b) represents this high energy change due to the removal of the fourth electron from a fully filled 2p6 orbital.