the values of observed and calculated molecular weights of silver nitrate are 90 and 170 respectively. the degree of dissociation of silver nitrate is

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Solution

Dear Student,

The computation are expressed below,

$f o r s i l v e r n i t r a t e t h e v a n t h o f f f a c t o r i s, i = \frac{N o r m a l m o l a r m a s s}{O b s e r v e d m o l a r m a s s} = 1 + α \frac{170}{90} = 1 + α α = \frac{170}{90} - 1 = 1.889 - 1 = 0.889 \Rightarrow α = 88.9 %$

Regards.

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the values of observed and calculated molecular weights of silver nitrate are 90 and 170 respectively. the degree of dissociation of silver nitrate is​

Dear Student, The computation are expressed below, for silver nitrate the vant hoff factor is,i =Normal molar massObserved molar mass=1+α17090=1+αα=17090-1=1.889-1=0.889 ⇒α=88.9 % Regards.

the values of observed and calculated molecular weights of silver nitrate are 90 and 170 respectively. the degree of dissociation of silver nitrate is